Thought Toys · Cycles & change · Exhibit 65

No spike, no matter how long you wait

Push current into a neuron and its voltage climbs toward a ceiling set by how much current arrives. If that ceiling sits below the threshold that triggers a spike, more time never helps — the voltage gets closer and closer, forever, without ever quite touching it. Cross the ceiling above threshold, though, and firing turns on and keeps going, like clockwork.

Membrane voltage over time voltage V(t) threshold Vth steady state Vss

Try it
your turn — drag I just past the rheobase line and watch waiting finally pay off

What you're seeing

Current trickles into the neuron and voltage rises — but the neuron also leaks, bleeding voltage away at a rate proportional to how high it already is. Those two effects settle into a tug-of-war with a fixed outcome: voltage climbs toward a steady ceiling Vss = R·I and, left alone, never overshoots it. If that ceiling sits at or below the firing threshold, the neuron spends forever approaching a wall it can never quite reach — this is the whole point: below a sharp line on the current dial, no amount of patience produces a spike. Not "a very long wait." Never.

Nudge the current a hair above that line — the exact boundary is I = Vth/R, the rheobase — and the ceiling now sits above threshold. Voltage reaches it, fires, resets instantly to zero, and starts the climb again: a perfectly regular rhythm. Right near the boundary that rhythm is glacially slow — the interval between spikes grows without any ceiling of its own as you creep toward rheobase from above — but firing itself was never a matter of degree. It's a hard yes or no, decided entirely by whether the ceiling clears the bar.

The rule, exactly. Voltage obeys τ dV⁄dt = V + RI, solved exactly by V(t) = Vss(1e−t/τ), Vss = RI, which never crosses Vth if Vss ≤ Vth. The rheobase Irh = Vth ⁄ R is the exact firing boundary, and above it the inter-spike interval is T = τ ln( Vss ⁄ (Vss Vth) ). Verified in node (improve/verify/65-neuron.js): the closed form solves the ODE exactly, checked against an independent finite-difference derivative across four (τ, Vss) pairs; subthreshold current produces exactly zero spikes over a 50τ horizon across four parameter sets, with voltage settling at or under threshold; suprathreshold simulated spike times match the closed-form interval to within 0.1% across four parameter sets and many consecutive spikes; the rheobase boundary is exact — current 3% below never fires over 80τ, 3% above always does; doubling the membrane resistance halves the rheobase to within 1e-12, across three cases. Negative control: the firing rate is exactly zero at or below rheobase and strictly increasing above it, and as current approaches rheobase from ever closer — down to one part in a million — the interval between spikes keeps climbing with no ceiling of its own, confirmed numerically across six shrinking gaps rather than merely asserted.

Also in Cycles & change: A perfect engine still throws most of it away →

All 18 in Cycles & change
  1. 04Predator & prey
  2. 102Infinite fuel. Finite speed.
  3. 112The best moment to give up on a good patch
  4. 118The growth stops. The growing doesn't.
  5. 122Why the cicadas wait a prime number of years
  6. 16The epidemic threshold
  7. 17Compound interest
  8. 53A feedback loop that overshoots
  9. 54Why planets speed up near the star
  10. 55The enzyme that hits a ceiling
  11. 65No spike, no matter how long you wait — you are here
  12. 68A perfect engine still throws most of it away
  13. 71Squeeze a reaction and it pushes back
  14. 73The switch that won't switch back
  15. 75Below a threshold, a population can't come back
  16. 80A bigger dose doesn't get there faster
  17. 83Come too close and a moon becomes a ring
  18. 95A system about to collapse gets slow before it goes.

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